document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189199>Question 1189199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x=           P(x) = \r<BR>\n" );
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document.write( "0             0.68<BR>\n" );
document.write( "1             0.2<BR>\n" );
document.write( "2             0.06<BR>\n" );
document.write( "3             0.04<BR>\n" );
document.write( "4             0.02\r<BR>\n" );
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document.write( "Find P(X>1). Ans: 0.12. I don't understand how to find the P. Shouldn't it be zero? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820522 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "Given table:<BR>\n" );
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document.write( "<tr><TD >X</TD><TD >P(X)</TD></tr><tr><TD >0</TD><TD >0.68</TD></tr><tr><TD >1</TD><TD >0.2</TD></tr><tr><TD >2</TD><TD >0.06</TD></tr><tr><TD >3</TD><TD >0.04</TD></tr><tr><TD >4</TD><TD >0.02</TD></tr>\n" );
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document.write( "P(X>1) is asking you to add up all of the probabilities in the second column that correspond to X values larger than 1.\r<BR>\n" );
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document.write( "So we'll add up these probabilities: {0.06, 0.04, 0.02} since they correspond to X = 2 through X = 4.\r<BR>\n" );
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document.write( "0.06+0.04+0.02 = 0.12\r<BR>\n" );
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document.write( "That's why P(X>1) = 0.12<BR>\n" );
document.write( "There's a 12% chance of X being larger than 1.\r<BR>\n" );
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document.write( "As the tutor Boreal pointed out, you can take a (slight) shortcut in adding the probabilities for X = 0 and X = 1, then subtracting that sum from 1. This is because P(A) + P(B) = 1 where A is the event of getting X to be 0 or 1; while B is the event of getting X > 1. One or the other must happen. The events are complementary. We can rearrange that previous equation into P(B) = 1 - P(A).<BR>\n" );
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