document.write( "Question 1189197: How many kilograms of coffee worth 94p/kg must be mixed with coffee worth £1.10/kg to give 12kg of coffee worth 95p/kg? \n" ); document.write( "

Algebra.Com's Answer #820498 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Apparently the other tutor doesn't read money amounts in pence and pounds....

\n" ); document.write( "Formally, a traditional formal algebraic setup would be something like this:
\n" ); document.write( "(x)kg at 0.94/kg, plus (12-x)kg at 1.10/kg, equals 12kg at 0.95/kg:
\n" ); document.write( " $\"0.94%28x%29%2B1.10%2812-x%29=0.95%2812%29\"$

\n" ); document.write( "I leave it to you to solve that....

\n" ); document.write( "Informally, here is a quick and easy way to solve any 2-part \"mixture\" problem like this:
\n" ); document.write( "On a number line, look at the three prices per kg -- 0.94, 0.95, and 1.10 -- and observe/calculate that 0.95 is 1/16 of the way from 0.94 to 1.10.
\n" ); document.write( "That means 1/16 of the mixture is the higher priced coffee.

\n" ); document.write( "ANSWER: 1/16 of 12kg, or 0.75kg, of the coffee worth 1.10 per kg; the other 11.25kg of the coffee worth 0.94 per kg.

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