document.write( "Question 1189173: Please explain how to solve this:\r
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Algebra.Com's Answer #820486 by rothauserc(4718)\"\" \"About 
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8.a Since the point (-8, 34, n) lies on I(1), we know that
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\n" ); document.write( "-8 = 3 -t
\n" ); document.write( "34 = 1+3t
\n" ); document.write( "n = 2 +2t
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\n" ); document.write( "3 -t = -8
\n" ); document.write( "-t = -11
\n" ); document.write( "t = 11
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\n" ); document.write( "n = 2 +2(11) = 24
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\n" ); document.write( "8.b Two vectors are perpendicular if their dot product is 0
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\n" ); document.write( "We are given that the lines intersect at point A, then
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\n" ); document.write( "-8 = 1 -s
\n" ); document.write( "34 = -2 +s*p
\n" ); document.write( "24 = u +s*q
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\n" ); document.write( "1 -s = -8
\n" ); document.write( "s = 9
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\n" ); document.write( "34 = -2 +9p
\n" ); document.write( "9p = 36
\n" ); document.write( "p = 4
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\n" ); document.write( "24 = u +9q
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\n" ); document.write( "Let t = 0 and s = 0, then
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\n" ); document.write( "vector v = <3-(-8), 1-34, 2-24> = <11, -33, -22>
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\n" ); document.write( "vector w = <1-(-8), -2-34, u-24> = <9, -36, u-24>
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\n" ); document.write( "The dot product of vectors w and v is 0, therefore
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\n" ); document.write( "9 * 11 +(-33)*(-36) +(-22)*(u-24) = 0
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\n" ); document.write( "99 +1188 -22u +528 = 0
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\n" ); document.write( "-22u +1815 = 0
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\n" ); document.write( "u = 82.5
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\n" ); document.write( "We know that
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\n" ); document.write( "24 = u +9q
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\n" ); document.write( "82.5 +9q = 24
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\n" ); document.write( "9q = -58.5
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\n" ); document.write( "q = -6.5
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\n" ); document.write( "Therefore,
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\n" ); document.write( "p = 4, q = -6.5, u = 82.5
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