document.write( "Question 1189181: Two kayakers paddle 18 km downstream with the current in the same time it takes them to go 8 km upstream against the current. The rate of the current is 3 km/hr. What is the rate of the kayakers in still water?\r
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Algebra.Com's Answer #820448 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "Two kayakers paddle 18 km downstream with the current in the same time it takes them to go 8 km upstream against the current.
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document.write( "Let x be the rate of the kayakers in still water.\r\n" );
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document.write( "Then the rate paddling downstream is (x+3) km/h; time paddling downstream is  \"18%2F%28x%2B3%29\" hours.\r\n" );
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document.write( "     the rate paddling   upstream is (x-3) km/h; time paddling   upstream is  \"18%2F%28x-3%29\" hours.\r\n" );
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document.write( "The times are the same, giving this time equation\r\n" );
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document.write( "    \"18%2F%28x%2B3%29\" = \"8%2F%28x-3%29\".\r\n" );
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document.write( "Solve by cross-multiplying\r\n" );
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document.write( "    18*(x-3) = 8*(x+3)\r\n" );
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document.write( "    18x - 54 = 8x + 24\r\n" );
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document.write( "    18x - 8x = 24 + 54\r\n" );
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document.write( "       10x   =   78\r\n" );
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document.write( "         x   =  78/10 = 7.8 km/h\r\n" );
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document.write( "ANSWER.  The rate of kayakers in still water is  7.8 km/h.\r\n" );
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document.write( "CHECK.  The time paddling downstream is  \"18%2F%287.8%2B3%29\" = \"18%2F10.8\" hours = \"180%2F108\" = \"10%2F6\" hours = 100 minutes.\r\n" );
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document.write( "        The time paddling   upstream is  \"8%2F%287.8-3%29\" = \"8%2F4.8\" = \"80%2F48\" hours = \"10%2F6\"  hours = 100 minutes.   ! Correct ! \r\n" );
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