document.write( "Question 1189052: Find the volume of the solid formed when a circular sector of radius 6 cm and angle of 30° is revolved about its angle bisector. \n" ); document.write( "
Algebra.Com's Answer #820404 by Alan3354(69443)\"\" \"About 
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Find the volume of the solid formed when a circular sector of radius 6 cm and angle of 30° is revolved about its angle bisector.
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\n" ); document.write( "Find the height of the spherical segment:
\n" ); document.write( "h = 6 - 6*cos(15) =~ 0.204445
\n" ); document.write( "\"Vol+=+2pi%2Ar%5E2h%2F3\"
\n" ); document.write( "Vol =~ 15.41479 cc
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\n" ); document.write( "\"cos%2815%29+=+%28sqrt%286%29+%2B+sqrt%282%29%29%2F4\" if you want an exact solution.
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\n" ); document.write( "You can split it into a cone and a spherical segment and do it that way, but it's more work.
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