document.write( "Question 1189143: 15 of 31 measurements are below 10 cm and 12 measurements are above 11 cm. Find the median if the other 4 measurements are 10.1 cm. 10.4 cm, 10.7 cm and 10.9 cm. Please explain how to solve. \n" ); document.write( "
Algebra.Com's Answer #820397 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "1) median position: \"%2831%2B1%29%2F2+=+16\"\r
\n" ); document.write( "\n" ); document.write( "\"15\" are below \"10\", so \"16\"th would be the first one to be greater than/equal to \"10\" which is \"10.1\"\r
\n" ); document.write( "\n" ); document.write( "2) \"median+=+12\" of \"9\" values\r
\n" ); document.write( "\n" ); document.write( "So \"5\"th value is \"12\"\r
\n" ); document.write( "\n" ); document.write( "\"7%2C9%2C11%2C12%2C13%2C14%2C17%2C19\" are the other \"+8\" values\r
\n" ); document.write( "\n" ); document.write( "To find the last measurement, use\"+mean+=+12\"\r
\n" ); document.write( "\n" ); document.write( "\"Sum+=+12%2A9+=+108\"\r
\n" ); document.write( "\n" ); document.write( "\"7%2B9%2B11%2B12%2B13%2B14%2B17%2B19%2Bx+=+108\"\r
\n" ); document.write( "\n" ); document.write( "\"102+%2B+x+=+108\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+6\"\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "1) \"10.1\"\r
\n" ); document.write( "\n" ); document.write( "2) \"6+\"and \"12\"\r
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