document.write( "Question 1186987: A part of P10,000 is invested at 4% and the remainder at 3. ½%. The annual
\n" ); document.write( "income from both is P380. Find the amount of each investment.
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Algebra.Com's Answer #820396 by Boreal(15235)\"\" \"About 
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x at 4% for 0.04x interest
\n" ); document.write( "10000-x at 0.035 for 350-0.035x
\n" ); document.write( "those two add to 380
\n" ); document.write( "so 350+0.005x=380
\n" ); document.write( "0.005x=30
\n" ); document.write( "x=6000 at 4% (240)
\n" ); document.write( "10000-x=4000 at 3.5% (140)
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