document.write( "Question 1186997: Bank customers arrive randomly on weekday afternoons at an average of 3.2 customers every 4 minutes.
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\n" ); document.write( "What is the probability of having more than 7 customers in a 4-minute interval on a weekday afternoon?
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Algebra.Com's Answer #820393 by Boreal(15235)\"\" \"About 
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this is a Poisson distribution with number proportional to time, no upper bound.
\n" ); document.write( "the probability for 8 is e^(-3.2)*3.2^8/8=0.0111
\n" ); document.write( "for 9 it is e^(-3.2)*3.2^9/9!=0.0039
\n" ); document.write( "for 10 it iii 0.0013
\n" ); document.write( "for 11 it is 0.0004
\n" ); document.write( "on the calculator, use 1-poisssoncdf(3.2, 7) ENTER. The 1- tells the calculator you want everything to the right, not left, and the arguments are the Poisson parameter and the last value you don't want to count, in this case 7.\r
\n" ); document.write( "\n" ); document.write( "=0.0168
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