document.write( "Question 1189131: Use direct proof to prove that the sum of two odd integers say a and b is even. Note
\n" );
document.write( " that we have discussed an odd number to be represented by 2n+1 and even as 2n. \n" );
document.write( "
Algebra.Com's Answer #820383 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Use direct proof to prove that the sum of two odd integers say a and b is even. Note \n" ); document.write( "that we have discussed an odd number to be represented by 2n+1 and even as 2n. \n" ); document.write( "~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let \"a\" and \"b\" be odd integer numbers.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then, as you discussed earlier, a = 2n+1, b = 2m+1 for some integer numbers \"m\" and \"n\".\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It implies that a + b = (2n+1) + (2m+1) = 2n + 1 + 2m + 1 = 2n + 2m + 2 = 2*(n+m+1).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus the sum a + b is an integer number of the form 2k, where integer number \"k\" is n+m+1.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It means that a + b is an even number.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "The proof is complete.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |