document.write( "Question 1189116: Two lines L1 :2y-3x-6=0and L2 :3y+x-20=0 intersect at point A. A third line L3 is perpendicular to L2 at point A. Find the equation of L3 in the Form y=mx+c where m and c are constants \n" ); document.write( "
Algebra.Com's Answer #820366 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! find the intersection point. \n" ); document.write( "From L2, x=20-3y \n" ); document.write( "so 2y-60+9y-6=0 by substitution \n" ); document.write( "11y=66 \n" ); document.write( "y=6 \n" ); document.write( "x=2 \n" ); document.write( "They intersect at (2, 6) \n" ); document.write( "L2 equation is also y=(-1/3)x+20/3 \n" ); document.write( "slope of the desired line is negative reciprocal of -1/3 or 3 \n" ); document.write( "point slope formula is y-y1=m (x-x1),m slope,(x1, y1) point \n" ); document.write( "y-6=3(x-2) \n" ); document.write( "y=3x or y=3x+0.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |