document.write( "Question 1189116: Two lines L1 :2y-3x-6=0and L2 :3y+x-20=0 intersect at point A. A third line L3 is perpendicular to L2 at point A. Find the equation of L3 in the Form y=mx+c where m and c are constants \n" ); document.write( "
Algebra.Com's Answer #820366 by Boreal(15235)\"\" \"About 
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find the intersection point.
\n" ); document.write( "From L2, x=20-3y
\n" ); document.write( "so 2y-60+9y-6=0 by substitution
\n" ); document.write( "11y=66
\n" ); document.write( "y=6
\n" ); document.write( "x=2
\n" ); document.write( "They intersect at (2, 6)
\n" ); document.write( "L2 equation is also y=(-1/3)x+20/3
\n" ); document.write( "slope of the desired line is negative reciprocal of -1/3 or 3
\n" ); document.write( "point slope formula is y-y1=m (x-x1),m slope,(x1, y1) point
\n" ); document.write( "y-6=3(x-2)
\n" ); document.write( "y=3x or y=3x+0.\r
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