document.write( "Question 1189095: A soft drink machine is regulated so that it discharges an average of 200 milliliters per cup. If the\r
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document.write( "amount of drink is normally distributed with a standard deviation equal to 15 millimeters, a) what fraction of the cups will contain more than 240 milliliters?\r
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document.write( "b) c) what is the probability that a cup contains between 191 and 209 milliliters? how many cups will likely overflow if 230 milliliters cups are used for the next 1000 di\r
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document.write( "d)\r
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document.write( "below what value do we get the smallest 25% of the drinks?
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Algebra.Com's Answer #820351 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z(240)>(240-200/15 or +2.67 \n" ); document.write( "probability z> 2.67=0.0038 \n" ); document.write( "- \n" ); document.write( "between 191 and 209 is the same way. \n" ); document.write( "calculator 2ndVARS(191,209,200,15) and that will equal twice the probability of z=9/15 or -.6 \n" ); document.write( "- \n" ); document.write( "230 ml cups are two sd over or 0.02275 probability, so 22.75 or 23 cups would be expected to overflow \n" ); document.write( "- \n" ); document.write( "z(0.25)=-0.6745=(x-200)/15 \n" ); document.write( "-10.12=x-200 \n" ); document.write( "x=189.88 or 190 ml\r \n" ); document.write( "\n" ); document.write( "Note: there is an error in the problem. The SD is 15 milliliters. All units are in ml.\r \n" ); document.write( "\n" ); document.write( " |