document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189097>Question 1189097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express the following as a single logarithm and simplify.\r<BR>\n" );
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document.write( "• 3/4 loga x - 1/2 loga y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820330 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start off with 3/4 * loga(x) - 1/2 * loga(y)\r<BR>\n" );
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document.write( "this becomes:\r<BR>\n" );
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document.write( "loga(x^(3/4) - loga(y^(1/2)) which becomes:\r<BR>\n" );
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document.write( "loga(x^(3/4) / y^(1/2))\r<BR>\n" );
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document.write( "i confirmed by letting x = 7 and y = 3 and a = 10.\r<BR>\n" );
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document.write( "the original equation becamre:\r<BR>\n" );
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document.write( "3/4 * log10(7) - 1/2 * log10(3) = .3952629027\r<BR>\n" );
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document.write( "this became:\r<BR>\n" );
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document.write( "log10(7^1/4) / 3^(1/2)) = .3952629027.\r<BR>\n" );
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document.write( "this confirms the conversion is correct.\r<BR>\n" );
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document.write( "your solution is loga(x^(3/4) / y^(1/2)).\r<BR>\n" );
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document.write( "it is simplified as best i can determine.\r<BR>\n" );
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document.write( "if that's not the answer they are looking for, let me know what is and i'll explain how they got it.\r<BR>\n" );
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document.write( "theo\r<BR>\n" );
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document.write( " </SPAN>\n" );
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