document.write( "Question 1188966: A student has committed the errors which follows the Poisson distribution
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document.write( "with an average rate of 1.5 errors per class.
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document.write( "i) What is the probability that she makes at least 3 errors during one class?
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document.write( "ii) What is the probability that she has committed two ‘error-free’ classes in
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document.write( "the two weeks? \n" );
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Algebra.Com's Answer #820288 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! this is e^(-1.5)*1.5^3/3!=0.1255 \n" ); document.write( "this issue e^(-1.5)*1.5^0/0!=0.2231 per week and square that for two weeks = 0.04979 \n" ); document.write( " |