document.write( "Question 1189043: Hi
\n" ); document.write( "Andrew spent $682 on a pendent. He spent 1/10 of the remaining money on a ring. If he still had 3/7 of his money left. How much did he have at first. \r
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Algebra.Com's Answer #820267 by ikleyn(52794) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "Andrew spent $682 on a pendent. He spent 1/10 of the remaining money on a ring.
\n" ); document.write( "If he still had 3/7 of his money left. How much did he have at first.
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document.write( "Let x = how much did he have at first.\r\n" );
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document.write( "Then (x-682 is remaining money after spending  $682;\r\n" );
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document.write( "     (9/10)*(x-682) is remaining money after spending 1/10 on the ring.\r\n" );
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document.write( "Equation\r\n" );
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document.write( "     = .\r\n" );
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document.write( "To solve, multiply both sides by 70 and simplify\r\n" );
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document.write( "    9*7*(x-682) = 30x\r\n" );
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document.write( "    63x - 63*682 = 30x\r\n" );
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document.write( "    63x - 30x = 63*682  \r\n" );
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document.write( "       33x    = 63*682\r\n" );
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document.write( "         x    =  = 1302.\r\n" );
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document.write( "ANSWER.  Andrew had $1302 at first.\r\n" );
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