document.write( "Question 1189026: Hello all, could you please help me with this problem? Would greatly appreciate the help.
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Algebra.Com's Answer #820251 by ikleyn(52778)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Since the shown angles are equal, the shown segments inside triangle are bisectors of respective angles.\r\n" );
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document.write( "    |    In any triangle, bisector of an angle divides the opposite side   |\r\n" );
document.write( "    |        in the ratio equal to the ratio of adjacent sides.            |\r\n" );
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document.write( "THEREFORE, in the given triangle  \"y%2Fz\" = \"6%2F4\"  and  y + z = 5.\r\n" );
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document.write( "    So, the side of the length 5 is divided in the ratio 6:4.\r\n" );
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document.write( "    It means that y = \"5%2A%286%2F10%29\" = \"6%2F2\" = 3;  z = 5-3 = 2.\r\n" );
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document.write( "Similarly, side of the length 6 is divided in propoprtion  \"x%2Fw\" = \"5%2F4\".\r\n" );
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document.write( "    So, the side of the length 6 is divided in the ratio 5:4.\r\n" );
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document.write( "    It means that  x = \"6%2A%285%2F9%29\" = \"30%2F9\" = \"10%2F3\" = 3 \"1%2F3\",  w = 6 - 3 \"1%2F3\" = 2 \"2%2F3\".\r\n" );
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document.write( "ANSWER.  x = 3 \"1%2F3\";  y = 3;  z = 2;  w = 2 \"2%2F3\".\r\n" );
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