document.write( "Question 1188882: A doctor at a local hospital is interested in estimating the birth weight of infants. How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean? Assume that s = 7 ounces based on earlier studies. \n" ); document.write( "
Algebra.Com's Answer #820230 by Theo(13342)\"\" \"About 
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i get the following:\r
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\n" ); document.write( "\n" ); document.write( "standard error = standard deviation divided by square root of sample size.\r
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\n" ); document.write( "\n" ); document.write( "when the standard deviation is 7, then the standard error is 7/sqrt(n).\r
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\n" ); document.write( "\n" ); document.write( "n is the sample size.\r
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\n" ); document.write( "\n" ); document.write( "critical z-score at 90% confidence interval is plus or minus 1.645.\r
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\n" ); document.write( "\n" ); document.write( "z-score formula is z = (x - m) / s\r
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\n" ); document.write( "\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the mean
\n" ); document.write( "s is the standard error.\r
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\n" ); document.write( "\n" ); document.write( "you are looking for (x - m) to be equal to plus or minus 4.\r
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\n" ); document.write( "\n" ); document.write( "on the high side, your formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "1.645 = 4 / (7 / sqrt(n)).\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 7 / sqrt(n) to get:\r
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\n" ); document.write( "\n" ); document.write( "1.645 * 7 / sqrt(n) = 4.\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by sqrt(n) and divide both sides of this equation by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "1.645 * 7 / 4 = sqrt(n)\r
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\n" ); document.write( "\n" ); document.write( "solve for sqrt(n) t9 get:\r
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\n" ); document.write( "\n" ); document.write( "sqrt(n) = 2.87875.\r
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\n" ); document.write( "\n" ); document.write( "solve for standard error to get:\r
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\n" ); document.write( "\n" ); document.write( "standard error = 7 / sqrt(n) = 7 / 2.87875 = 2.431610942.\r
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\n" ); document.write( "\n" ); document.write( "that's the standard error that should get you a margin of error of plus or minus 4.\r
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\n" ); document.write( "\n" ); document.write( "on the high side, (x - m) would be equal to 4.
\n" ); document.write( "on the low side, (x - m) would be equal to -4.\r
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\n" ); document.write( "\n" ); document.write( "1.645 * 2.431618942 = 4
\n" ); document.write( "-1.645 * 2.431618942 = -4\r
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\n" ); document.write( "\n" ); document.write( "this result was achieved with a sample size of 2.87875 ^ 2 = 8.287201563.\r
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\n" ); document.write( "\n" ); document.write( "since a sample size can't be a fraction of a whole number, then you need to go up to the next highest integer to get a minimum sample size of at least 9.\r
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\n" ); document.write( "\n" ); document.write( "with a sample size of at least 9, your margin of error will be within plus or minus 4.
\n" ); document.write( "in fact, it will be within less than plus or minus 4.\r
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\n" ); document.write( "\n" ); document.write( "with a sample size of 9, standard error = 7 / sqrt(sample size) = 7/sqrt(9) = 7/3 = 2.333333333.\r
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\n" ); document.write( "\n" ); document.write( "1.645 = (x - m) / 2.333333333.....
\n" ); document.write( "(x - m) = 1.645 * 2.3333333..... = 3.838333333.....
\n" ); document.write( "-1.645 = (x - m) / 2.3333333.....
\n" ); document.write( "(x - m) = -1.645 * 2.333333..... = -3.83833333.....\r
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\n" ); document.write( "\n" ); document.write( "the mean can be anything and you will always get a margin of error within plus or minus 3.83833333..... as long as the sample size is greater than or equal to 9.\r
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\n" ); document.write( "\n" ); document.write( "as an example, assume the mean is 100.\r
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\n" ); document.write( "\n" ); document.write( "on the high side, 1.645 = (x - 100) / 2.33333.....
\n" ); document.write( "solve for x to get:
\n" ); document.write( "X = 1.645 * 2.3333..... + 100 = 103.8383333.....
\n" ); document.write( "on the low side, x = -1.645 * 2.333..... + 100 = 96.16166666.....\r
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\n" ); document.write( "\n" ); document.write( "103 - 100 = 3.83833333......
\n" ); document.write( "100 - 96.16166666..... = 3.83833333.....\r
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\n" ); document.write( "\n" ); document.write( "note that, every time you increase the sample size, the standard error gets smaller as long as the standard deviation remains the same.\r
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\n" ); document.write( "\n" ); document.write( "it has to be recalculated every time the sample size is changed.\r
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\n" ); document.write( "\n" ); document.write( "as another example, assume the sample size is 16.
\n" ); document.write( "the standard error becomes 7 / sqrt(16) = 7/4 = 1.75.\r
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\n" ); document.write( "\n" ); document.write( "1.645 = (x - m) / 1.75 gets you (x - m) = 1.75 * 1.645 = 2.87875.\r
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\n" ); document.write( "\n" ); document.write( "the standard error gets smaller and the margin of error becomes smaller as well.\r
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\n" ); document.write( "\n" ); document.write( "the solution to this problem is that the sample size needs to be greater than or equal to 9.
\n" ); document.write( "this allows the margin of error to be less than 4.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo\r
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