document.write( "Question 1189011: Mary is three times as old as Jill. In five years, she will be twice as old as Jill. Find the present age of Mary.
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Algebra.Com's Answer #820224 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Jill is x years old\r\n" ); document.write( "\r\n" ); document.write( "Mary is 3x years old.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In 5 years\r\n" ); document.write( "\r\n" ); document.write( " 3x + 5 = 2*(x+5).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and find x\r\n" ); document.write( "\r\n" ); document.write( " 3x + 5 = 2x + 10\r\n" ); document.write( "\r\n" ); document.write( " 3x - 2x = 10 - 5\r\n" ); document.write( "\r\n" ); document.write( " x = 5\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. Mary is 3x = 3*5 = 15 years old now.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |