document.write( "Question 1189011: Mary is three times as old as Jill. In five years, she will be twice as old as Jill. Find the present age of Mary.
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Algebra.Com's Answer #820224 by ikleyn(52790)\"\" \"About 
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document.write( "Jill is x  years old\r\n" );
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document.write( "Mary is 3x years old.\r\n" );
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document.write( "In 5 years\r\n" );
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document.write( "    3x + 5 = 2*(x+5).\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    3x + 5 = 2x + 10\r\n" );
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document.write( "    3x - 2x = 10 - 5\r\n" );
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document.write( "       x    =    5\r\n" );
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document.write( "ANSWER.  Mary is 3x = 3*5 = 15 years old now.\r\n" );
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