document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188988>Question 1188988</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Framing a Painting Ali paints with watercolors on a sheet of paper 50 cm wide by 38 cm high. He then<BR>\n" );
document.write( "places this sheet on a mat so that a uniformly wide strip of the mat shows all around the picture. The<BR>\n" );
document.write( "perimeter of the mat is 256 cm. How wide is the strip of the mat showing around the picture?Vic </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820190 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Framing a Painting Ali paints with watercolors on a sheet of paper 50 cm wide by 38 cm high.<BR>\n" );
document.write( " He then places this sheet on a mat so that a uniformly wide strip of the mat shows all around the picture.<BR>\n" );
document.write( " The perimeter of the mat is 256 cm.<BR>\n" );
document.write( " How wide is the strip of the mat showing around the picture?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let x = the width of the strip around the picture<BR>\n" );
document.write( "let L = the length of the mat<BR>\n" );
document.write( "let w = the width of the mat<BR>\n" );
document.write( ":<BR>\n" );
document.write( "perimeter<BR>\n" );
document.write( "2L + 2w = 256<BR>\n" );
document.write( "divide equation by 2<BR>\n" );
document.write( "L + w = 128<BR>\n" );
document.write( "w = (128-L), use this form for substitution<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the values using the picture dimensions<BR>\n" );
document.write( "L-2x = 50<BR>\n" );
document.write( "and<BR>\n" );
document.write( "w-2x = 38<BR>\n" );
document.write( "replace w with (128-L)<BR>\n" );
document.write( "(128-L) - 2x = 38<BR>\n" );
document.write( "-L - 2x = 38 - 128<BR>\n" );
document.write( "-L - 2x = -90<BR>\n" );
document.write( "L + 2x = 90<BR>\n" );
document.write( "Subtract from the 1st equation<BR>\n" );
document.write( "L - 2x = 50<BR>\n" );
document.write( "L + 2x = 90<BR>\n" );
document.write( "-------------Subtraction eliminates L, find x<BR>\n" );
document.write( "0 - 4x = -40<BR>\n" );
document.write( "x = -40/-4<BR>\n" );
document.write( "x = 10 cm is the width around the picture<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );