document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188986>Question 1188986</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Dimensions of a Lot A rectangular parcel of land is 50 m wide. The length of a diagonal between opposite<BR>\n" );
document.write( "corners is 10 m more than the length of the parcel. What is the length of the parcel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820189 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the lot is 50 meters wide.<BR>\n" );
document.write( "the length of a diagonal between opposite corners is 10 meters more than the length.\r<BR>\n" );
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document.write( "my diagram is shown below that that visualize your problem.\r<BR>\n" );
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document.write( "the diagonal forms the length of the hypotenuse of a right triangle whose legs are L and W.<BR>\n" );
document.write( "when W = 50 cm, the legs becomes L and 50.<BR>\n" );
document.write( "the hypotenuse, being 10 meters more than the length, is equal to L + 10.\r<BR>\n" );
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document.write( "by pythagorus, L^2 + 50^2 = (L + 10)^2<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "L^2 + 2500 = L^2 + 20L + 100<BR>\n" );
document.write( "subtract L^2 from both sides of the eqution to get:<BR>\n" );
document.write( "2500 = 20L + 100<BR>\n" );
document.write( "subtract 100 from both sides of the equation to get:<BR>\n" );
document.write( "2400 = 20L<BR>\n" );
document.write( "divide both sides of the equation by 20 to gt:<BR>\n" );
document.write( "120 = L<BR>\n" );
document.write( "since the hypotenuse is 10 meters more than the length, then the hypotenuse has to be 130.<BR>\n" );
document.write( "you get:<BR>\n" );
document.write( "120^2 + 50^2 = 130^2<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "16900 = 16900.<BR>\n" );
document.write( "this confirms the length of the hypotenuse is correct.<BR>\n" );
document.write( "this also confirms the length of the rectangle is correct.\r<BR>\n" );
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document.write( "your solution is that the length of the parcel is equal to 120 cm.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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