document.write( "Question 1188913: My father is 12 years more than twice my age. In 16 years, my father’s age will be 30
\n" ); document.write( "years less than three times my age. Find my age and my father’s age
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Algebra.Com's Answer #820102 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "(1) define a variable

\n" ); document.write( "let x = your age (now)

\n" ); document.write( "(2) use that variable to define expressions for the other numbers in the problem (your age 16 years from now; and your father's age now, and 16 years from now)

\n" ); document.write( "2x+12 = your father's age now

\n" ); document.write( "x+16 = your age 16 years from now
\n" ); document.write( "(2x+12)+16 = 2x+28 = your father's age 16 years from now

\n" ); document.write( "(3) Use those expressions to write an equation using the given information

\n" ); document.write( "\"In 16 years, my father’s age will be 30 years less than three times my age.\"

\n" ); document.write( "Rewrite that to put it exactly in terms of the expressions you have defined:

\n" ); document.write( "My father's age 16 years from now will be (is) 30 less than three times my age then (16 years from now):

\n" ); document.write( "2x+28 = 3(x+16)-30

\n" ); document.write( "(4) solve using basic algebra

\n" ); document.write( "I leave that to you....

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