document.write( "Question 1188902: A messenger, traveling 65 km/h, pursues a car which has a start of 2 hours, and
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document.write( "overtakes it in 3 hours. Find the car’s speed. \r
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Algebra.Com's Answer #820097 by Alan3354(69443) You can put this solution on YOUR website! A messenger, traveling 65 km/h, pursues a car which has a start of 2 hours, and \n" ); document.write( "overtakes it in 3 hours. Find the car’s speed. \n" ); document.write( "------------------- \n" ); document.write( "c = car's speed \n" ); document.write( "m = messenger's speed = 65 \n" ); document.write( "--- \n" ); document.write( "At the messenger's start, the car is 2c km ahead. \n" ); document.write( "The difference in speed is 65 - c \n" ); document.write( "--- \n" ); document.write( "3*(65-c) = 2c \n" ); document.write( "195 - 3c = 2c \n" ); document.write( "c = 39 km/hr \n" ); document.write( " |