document.write( "Question 1188844: A rectangle’s length is 5 feet shorter than twice its width. The rectangle’s perimeter is 110 feet. Find the rectangle’s length and width. \n" ); document.write( "
Algebra.Com's Answer #820041 by Alan3354(69443)\"\" \"About 
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A rectangle’s length is 5 feet shorter than twice its width. The rectangle’s perimeter is 110 feet. Find the rectangle’s length and width.
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\n" ); document.write( "2W + 2L = 110
\n" ); document.write( "W + L = 55
\n" ); document.write( "L = 2W - 5
\n" ); document.write( "Sub for L
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\n" ); document.write( "W + 2W-5 = 55
\n" ); document.write( "etc
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