document.write( "Question 1188844: A rectangle’s length is 5 feet shorter than twice its width. The rectangle’s perimeter is 110 feet. Find the rectangle’s length and width. \n" ); document.write( "
Algebra.Com's Answer #820041 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A rectangle’s length is 5 feet shorter than twice its width. The rectangle’s perimeter is 110 feet. Find the rectangle’s length and width. \n" ); document.write( "--------- \n" ); document.write( "2W + 2L = 110 \n" ); document.write( "W + L = 55 \n" ); document.write( "L = 2W - 5 \n" ); document.write( "Sub for L \n" ); document.write( "---- \n" ); document.write( "W + 2W-5 = 55 \n" ); document.write( "etc \n" ); document.write( " |