document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112392>Question 112392</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of the current in a river is 2mph. Jay travels 20 miles upstream and then 20 miles downstream in a total of 5 1/3 hr. Find the speed of his boat. <BR>\n" );
document.write( "- I know that the distance formula is supposed to be used to find this answer but i just cannot get it right. d=r.t </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82002 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20/(S-2)+20/(S+2)=5 1/3<BR>\n" );
document.write( "[20(S+2)+20(S-2)]/(S-2)(S+2)=16/3<BR>\n" );
document.write( "(20S+40+20S-40)/(S^2-4)=16/3 <BR>\n" );
document.write( "40S/(S^2-4)=16/3 NOW CROSS MULTIPLY<BR>\n" );
document.write( "16(S^2-4)=40S*3<BR>\n" );
document.write( "16S^2-64=120S<BR>\n" );
document.write( "16S^2-120S-64=0<BR>\n" );
document.write( "8(2S^2-15S-8)=0<BR>\n" );
document.write( "8(2S+1)(S-8)=0<BR>\n" );
document.write( "S-8=O<BR>\n" );
document.write( "S=8 ANSWER FOR THE SPEED OF THE BOAT.<BR>\n" );
document.write( "20/(8-2)+20/(8+2)=16/3<BR>\n" );
document.write( "20/6+20/10=16/3<BR>\n" );
document.write( "(20*10+20*6)/60=16/3<BR>\n" );
document.write( "(200+120)/60=16/3<BR>\n" );
document.write( "320/60=16/3<BR>\n" );
document.write( "16/3=16/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );