document.write( "Question 1188822: In the following problem:\r
\n" ); document.write( "\n" ); document.write( "3(x+4)(x+7)\r
\n" ); document.write( "\n" ); document.write( "To obtain a correct solution why must you multiply the binomials\r
\n" ); document.write( "\n" ); document.write( "Instead of distributing 3 to the first ? If you do this, it comes up incorrect.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #819999 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
In the following problem:\r
\n" ); document.write( "\n" ); document.write( "3(x+4)(x+7)\r
\n" ); document.write( "\n" ); document.write( "To obtain a correct solution why must you multiply the binomials\r
\n" ); document.write( "\n" ); document.write( "Instead of distributing 3 to the first ? If you do this, it comes up incorrect.
\n" ); document.write( "===================
\n" ); document.write( "Makes no difference what you do first.
\n" ); document.write( "3(x+4)(x+7) = (3x+12)*(x+7) = 3x^2 + 33x + 84
\n" ); document.write( "---
\n" ); document.write( "3(x+4)(x+7) = (x+4)*(3x+21) = 3x^2 + 33x + 84
\n" ); document.write( "---
\n" ); document.write( "3(x+4)(x+7) = 3(x^2+11X+28) = 3x^2 + 33x + 84
\n" ); document.write( "================
\n" ); document.write( "The only possible mistake is to multiply both binomials by 3.
\n" ); document.write( "
\n" );