document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188816>Question 1188816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the smaller angle (Ac) formed by the hands of the clock at 3:30 PM. Give the angle coterminal with angle Ac such that Ac is greater than or equal to 360 degrees and smaller than 720 degrees.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819998 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "There are many ways to set up this kind of problem for solving.  Here is the way I like best....<br><BR>\n" );
document.write( "I measure the number of degrees past \"noon\" that each of the hands of the clock has moved; then the angle between the hands is the difference of those two angles.<br><BR>\n" );
document.write( "At 3:30, the hour hand has moved 3.5 hours past noon at 30 degrees per hour (360 degrees in 12 hours), so it is 105 degrees past noon.<br><BR>\n" );
document.write( "At 3:30, the minute hand has clearly moved 180 degrees past noon.  However, to demonstrate the general solution method, it has moved for 30 minutes at 6 degrees per minute (360 degrees in 60 minutes), so it is 180 degrees past noon.<br><BR>\n" );
document.write( "So the angle between the two hands is 180-105 = 75 degrees.<br><BR>\n" );
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