document.write( "Question 1188684: Your cable company offers two cable plans. One plan costs a monthly fee of $45 and $2 per additional channel. The other plan costs a monthly fee of $30 and $3 per additional channel. For how many extra channels will the cost be the same amount? What is that cost? \n" ); document.write( "

Algebra.Com's Answer #819944 by MathTherapy(10555) $\"\"$ $\"About$

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\n" ); document.write( "Your cable company offers two cable plans. One plan costs a monthly fee of $45 and $2 per additional channel. The other plan costs a monthly fee of $30 and $3 per additional channel. For how many extra channels will the cost be the same amount? What is that cost?
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Let number of additional channels be C\r\n" );
document.write( "Then for plans to cost the same, we get: 2C + 45 = 3C + 30\r\n" );
document.write( "2C - 3C = 30 - 45\r\n" );
document.write( "    - C = - 15\r\n" );
document.write( "Number of additional channels to make both plans cost the same, or \r\n" );
document.write( "Substitute value of C into either side of the equation to get the cost!\r\n" );
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document.write( "That's IT!! Could this be any simpler?

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