document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112369>Question 112369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 35% alcohol solution is to be made by mixing 2 liters of 8% solution with pure alcohol. How much pure alcohol is required? Create a table with headings that include units, show equation, solve and include units in your answer.\r<BR>\n" );
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document.write( "Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81991 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81991\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> YOU DO THE TABLE<BR>\n" );
document.write( "Let x=amount of pure alcohol needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure alcohol needed (x) plus the amount of pure alcohol in the 8% solution (0.08*2) has to equal the amount of pure alcohol in the final solution (0.35(2+x)).  So our equation to solve is:\r<BR>\n" );
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document.write( "x+0.08*2=0.35(2+x)  get rid of parens and simplify<BR>\n" );
document.write( "x+0.16=0.7+0.35x  subtract 0.16 and also 0.35x from both sides\r<BR>\n" );
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document.write( "x+0.16-0.16-0.35x=0.7-0.16 collect like terms\r<BR>\n" );
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document.write( "0.65x=0.54  divide both sides by 0.65\r<BR>\n" );
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document.write( "x=0.83077-- liters----------------------amount of pure alcohol needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.83077+0.16=0.7+0.35*0.83077\r<BR>\n" );
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document.write( "0.990769=0.990769\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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