document.write( "Question 1188713: A body slide down an incline plane which make angle of 30° with the horizontal neglecting friction. Calculate
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Algebra.Com's Answer #819885 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "A body \"cross%28slide%29\" SLIDES down \"cross%28an%29\" AT incline plane which \"cross%28make%29\" MAKES angle of 30° with the horizontal.
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document.write( "(a)  Notice that the height \"h\" is half of the hypotenuse, since the angle with horizont is 30.\r\n" );
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document.write( "     So, the height is  \"10%2F2\" = 5 meters.\r\n" );
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document.write( "     The change of the potential energy between the levels h = 5 meters and h = 0 if  P = mgh,\r\n" );
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document.write( "     where m is the mass of the body in kilograms and h = 10m/s^2 is the gravity acceleration.\r\n" );
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document.write( "     This change of the potential energy is spent to increase the kinematic energy of the body \r\n" );
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document.write( "     from 0 to  \"%28mv%5E2%29%2F2\".  where v is the magnitude of the velocity at the end.\r\n" );
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document.write( "     So,   \"%28mv%5E2%29%2F2\" = mgh.   It is nothing elese as the energy conservation law in this problem.\r\n" );
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document.write( "     Canceling \"m\" in both sides, you get  \"v%5E2\" = 2gh,  or   v = \"sqrt%282gh%29\".\r\n" );
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document.write( "     The last step is to substitute h = 5 m,  g = 10 m/s^2  into this formula, and you get\r\n" );
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document.write( "         v = \"sqrt%282%2A10%2A5%29\" = \"sqrt%28100%29\" = 10 m/s.\r\n" );
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document.write( "ANSWER.  The final speed (the magnitude of the velocity) is 10 m/s.\r\n" );
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document.write( "(b)  In this problem, the speed rise from 0 to 10 m/s uniformly with time.\r\n" );
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document.write( "     Hence, the average speed is the average between 0 and 10 m/s,  which is 5 m/s.\r\n" );
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document.write( "     It implies that the time taken to slide is the full distance of 10 meters divided by the average speed of 5 m/s\r\n" );
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document.write( "        time taken to slide = \"10%2F5\" = 2 seconds.\r\n" );
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