document.write( "Question 112370: Find three consecutive even integers such that the first plus twice the second plus four times the third equals 174 \n" ); document.write( "

Algebra.Com's Answer #81987 by rajagopalan(174) $\"\"$ $\"About$

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Let the first number be x-2
\n" ); document.write( "The mid number ia x
\n" ); document.write( "Third Number is x+2
\n" ); document.write( "Adding the first plus twice the second plus four times the third we get:
\n" ); document.write( "....x-2
\n" ); document.write( "...2x
\n" ); document.write( "...4x+8
\n" ); document.write( "--------
\n" ); document.write( " 7x+6
\n" ); document.write( "--------
\n" ); document.write( "7x+6=174
\n" ); document.write( "7x=174-6=168
\n" ); document.write( "x=168/7=24
\n" ); document.write( "So the numbers are ....22, 24 and 26
\n" ); document.write( "Verification\r
\n" ); document.write( "\n" ); document.write( ".....22
\n" ); document.write( "+ 48
\n" ); document.write( "+ 104
\n" ); document.write( "-------
\n" ); document.write( " 174
\n" ); document.write( "-------- OK.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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