document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188401>Question 1188401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How you will find the coordinates of P(−9π/2) if you know the coordinates<BR>\n" );
document.write( "of P(π/2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819829 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How you will find the coordinates of P(−9π/2) if you know the coordinates<BR>\n" );
document.write( "of P(π/2)?<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Add 2pi repeatedly<BR>\n" );
document.write( "-9pi/2 + 2pi = -5pi/2<BR>\n" );
document.write( "---> -pi/2<BR>\n" );
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document.write( "-9pi/2 is coincident with -pi/2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "If the coordinates of P(pi/2) are (x,y) --> P(-pi/2) is (-x,-y) </SPAN>\n" );
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