document.write( "Question 1188683: The cost of admission to the Christmas Carnival was $50 for a group of 9 children and 2 adults. The admission was $60 for another group of 10 children and 4 adults. What was the admission price for each child? What was the admission price for each adult? \n" ); document.write( "
Algebra.Com's Answer #819824 by Boreal(15235)\"\" \"About 
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9C+2A=50; C=children, A=adult
\n" ); document.write( "10C+4A=60
\n" ); document.write( "multiply the top by -2 and add
\n" ); document.write( "-18C-4A=-100
\n" ); document.write( "10C+4A=60
\n" ); document.write( "-8C=-40
\n" ); document.write( "C=$5 for children
\n" ); document.write( "substitute into first
\n" ); document.write( "45+2A=-0
\n" ); document.write( "A=$2.50
\n" ); document.write( "-
\n" ); document.write( "check using second
\n" ); document.write( "10(5)+4(2.50)=60, and that is true.
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