document.write( "Question 1188683: The cost of admission to the Christmas Carnival was $50 for a group of 9 children and 2 adults. The admission was $60 for another group of 10 children and 4 adults. What was the admission price for each child? What was the admission price for each adult? \n" ); document.write( "

Algebra.Com's Answer #819823 by Shin123(626) $\"\"$ $\"About$

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Letting x be the cost of admission for 1 child, and y for 1 adult, we have $\"system%289x%2B2y=50%2C10x%2B4y=60%29\"$
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
\n" ); document.write( " $\"+system%28+%0D%0A++++9%5Cx+%2B+2%5Cy+=+50%2C%0D%0A++++10%5Cx+%2B+4%5Cy+=+60+%29%0D%0A++\"$ We'll use substitution. After moving 2*y to the right, we get:
\n" ); document.write( " $\"9%2Ax+=+50+-+2%2Ay\"$ , or $\"x+=+50%2F9+-+2%2Ay%2F9\"$ . Substitute that
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\n" ); document.write( " $\"10%2A%2850%2F9+-+2%2Ay%2F9%29+%2B+4%5Cy+=+60\"$ and simplify: So, we know that y=2.5. Since $\"x+=+50%2F9+-+2%2Ay%2F9\"$ , x=5.
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\n" ); document.write( " Answer: $\"system%28+x=5%2C+y=2.5+%29\"$ .
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\n" ); document.write( "\n" ); document.write( "Therefore, the admission for a child cost $5, and an adult $2.50. \n" ); document.write( "

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