document.write( "Question 1188652: A bacteria culture starts with 280 bacteria and grows at a rate proportional to its size. After 5 hours there will be 1400 bacteria. \r
\n" ); document.write( "\n" ); document.write( "A. What will the population be after 4 hours?\r
\n" ); document.write( "\n" ); document.write( "B. How long will it take the population to reach 2630? Give your answer accurate to 2 decimal places.
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Algebra.Com's Answer #819790 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i think this means that it grows at a constant rate.
\n" ); document.write( "for example, something like 10% of its size, no matter what its size is.\r
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\n" ); document.write( "\n" ); document.write( "the formula for that is f = p * (1 + r) ^ n\r
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\n" ); document.write( "\n" ); document.write( "f is the future value.
\n" ); document.write( "p is the present value
\n" ); document.write( "r is the rate of growth per time period.
\n" ); document.write( "n is the number of time periods.\r
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\n" ); document.write( "\n" ); document.write( "they state that it grows from 280 to 1400 in 5 hours.\r
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\n" ); document.write( "\n" ); document.write( "the formula becomes 1400 = 280 * (1 + r) ^ 5.
\n" ); document.write( "divide both sides of this formula by 280 to get:
\n" ); document.write( "1400/280 = (1 + r) ^ 5.
\n" ); document.write( "take the fifth root of both sides of this equation to get:
\n" ); document.write( "(1400/280)^(1/5) = 1 + r.
\n" ); document.write( "subtract 1 from both sides of this equation to get:
\n" ); document.write( "(1400/280)^(1/5) - 1 = r
\n" ); document.write( "solve for r to get:
\n" ); document.write( "r = .379729661
\n" ); document.write( "that's the rate of growth per hour.\r
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\n" ); document.write( "\n" ); document.write( "replace r in the original equation and solve for f to get:
\n" ); document.write( "f = 280 * (1 + .379729661) ^ 5 = 1400.\r
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\n" ); document.write( "\n" ); document.write( "the rate is good.
\n" ); document.write( "after 4 hours, the population will be:
\n" ); document.write( "f = 280 * (1 + .379729661) ^ 4 = 1014.691529.\r
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\n" ); document.write( "\n" ); document.write( "1014.691529 is your solution to question a.
\n" ); document.write( "i'm not sure how they want you to round this so i left it as is.\r
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\n" ); document.write( "\n" ); document.write( "to find how long it takes to grow to 2630, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "2630 = 280 * (1 + .379729661) ^ n
\n" ); document.write( "divide both sides of the equation to 280 and simplify the right side of the equation to get:
\n" ); document.write( "2630/280 = 1.379729661 ^ n
\n" ); document.write( "take the log of both sides of the equation to get:
\n" ); document.write( "log(2630/280) = log(1.379729661 ^ n)
\n" ); document.write( "since log(x^n) = n*log(x), this becomes:
\n" ); document.write( "log(2630/280) = n * log(1.379729661).
\n" ); document.write( "divide both sides of the equation by log(1.379729661) to get:
\n" ); document.write( "log(2630/280) / log(1.379729661) = n
\n" ); document.write( "solve for n to get:
\n" ); document.write( "n = 6.958794448.\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing n in the original equation and solving for f to get:
\n" ); document.write( "f = 280 * 1.379729661 ^ 6.958794448 = 2630.
\n" ); document.write( "round to 2 decimal places to get n = 6.96\r
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\n" ); document.write( "\n" ); document.write( "the equation can be graphed as shown below:\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo\r
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