document.write( "Question 1188611: two angles are complementary. the larger angle exceeds three times the smaller by 38°. what is the measure of each angle? \n" ); document.write( "
Algebra.Com's Answer #819721 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Two angles are called complementary when their measures add to \"90\"°. \r
\n" ); document.write( "\n" ); document.write( "let the larger angle be \"alpha\" and the smaller angle \"beta\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=90\" ..........eq.1\r
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\n" ); document.write( "\n" ); document.write( " if the larger angle exceeds \"three\" times the smaller by \"38\"°, we have \r
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\n" ); document.write( "\n" ); document.write( "\"alpha=3beta%2B38\" .........eq.2\r
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\n" ); document.write( "\n" ); document.write( "substitute \"alpha\" in eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"3beta%2B38%2Bbeta=90\" ..........eq.1, solve for \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"4beta=90-38\"\r
\n" ); document.write( "\n" ); document.write( "\"4beta=52\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=13\"°\r
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\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"alpha=3beta%2B38\" .........eq.2, substitute \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=3%2A13%2B38\" \r
\n" ); document.write( "\n" ); document.write( "\"alpha=77\"°\r
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