document.write( "Question 1188579: Mr.Ulep has a rectangular field with a length twice its width.If 4 feet are taken from the length and 3 feet are taken from the width, the area of the field is 150 square feet.Find the area of the original field \n" ); document.write( "
Algebra.Com's Answer #819703 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "a rectangular field with a length \"L\" twice its width \"W\"
\n" ); document.write( "\"L=2W\"......eq.1\r
\n" ); document.write( "\n" ); document.write( "If \"4\" feet are taken from the length and \"3\" feet are taken from the width, the area of the field is \"150\" square feet\r
\n" ); document.write( "\n" ); document.write( "\"%28L-4%29%28W-3%29=150\"...........eq.2, substitute \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"%282W-4%29%28W-3%29=150\"\r
\n" ); document.write( "\n" ); document.write( "\"2W%5E2+-+10W+%2B+12=150\"\r
\n" ); document.write( "\n" ); document.write( "\"2W%5E2+-+10W+%2B+12-150=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2W%5E2+-+10W+-138=0\".........divide by \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2+-+5W+-69=0\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2+-+5W+-69=0\"\r
\n" ); document.write( "\n" ); document.write( "using quadratic formula we get:\r
\n" ); document.write( "\n" ); document.write( "\"W+=+5%2F2+%2B+sqrt%28301%29%2F2=11.18+\"
\n" ); document.write( "or
\n" ); document.write( "\"W+=+5%2F2+-+sqrt%28301%29%2F2=-6.1746757\"-> disregard negative solution\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L=2%2A11.18=22.36\"\r
\n" ); document.write( "\n" ); document.write( " the area of the original field is:\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"A=22.36%2A11.18\"\r
\n" ); document.write( "\n" ); document.write( "\"A=249.99\"\r
\n" ); document.write( "\n" ); document.write( "rounded\r
\n" ); document.write( "\n" ); document.write( "\"A=250\"\r
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