document.write( "Question 1188526: A man has a collection of 19 coins worth $2.55. There are twice as many nickels as dimes. If the rest are quarters, how many quarters are there? \n" ); document.write( "

Algebra.Com's Answer #819643 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "A man has a collection of 19 coins worth $2.55. There are twice as many nickels as dimes.
\n" ); document.write( "If the rest are quarters, how many quarters are there?
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document.write( "x dimes, 2x nickels and 19-x-2x = 19-3x quarters.\r\n" );
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document.write( "Total money equation\r\n" );
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document.write( "    5*(2x) + 10*x + 25*(19-3x) = 255  cents.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    10x + 10x + 25*19 - 75x = 255\r\n" );
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document.write( "    (10 + 10 - 75)x         = 255 - 25*19\r\n" );
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document.write( "        -55x               = -220\r\n" );
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document.write( "           x               =  = 4.\r\n" );
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document.write( "4 dimes, 8 nickels and 19-4-8 = 7 quarters.\r\n" );
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document.write( "ANSWER.  7 quarters.\r\n" );
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