document.write( "Question 1188436: The revenue and cost equations for a product are R = x(75-0.0005x) and C = 30x + 250000
\n" ); document.write( "Where R and C are measured in dollars and x represents the number of units sold. How many units must be sold to obtain a profit of at least $750000?
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Algebra.Com's Answer #819629 by Shin123(626) $\"\"$ $\"About$

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The profit is revenue minus cost, so the profit is $\"x%2875-0.0005x%29-30x-250000=-0.0005x%5E2-45x-250000\"$ .
\n" ); document.write( "Since we want this to equal $750,000, we get
\n" ); document.write( " $\"-0.0005x%5E2%2B45x-250000=750000\"$
\n" ); document.write( " $\"-0.0005x%5E2%2B45x-1000000=0\"$
\n" ); document.write( "Dividing both sides by $\"-0.0005\"$ , we get
\n" ); document.write( " $\"x%5E2-90000x%2B2000000000\"$ .
\n" ); document.write( "Factoring, we have $\"%28x-40000%29%28x-50000%29=0\"$ .
\n" ); document.write( "Therefore, the solution is to sell either 40,000 or 50,000 units. \n" ); document.write( "

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