document.write( "Question 1188509: A ball is thrown vertically upward from the top of a building 64 feet tall with an initial velocity of 48 feet per second. The distances (in feet) of the ball from the ground
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document.write( "after t seconds is s(t) = 64 + 48t - 1612.
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document.write( "(a) After how many seconds does the ball strike the ground?
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document.write( "(b) After how many seconds will the ball pass the top of the building on its way down? \n" );
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Algebra.Com's Answer #819622 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The formula is s(t)=-16t^2+48t+64 \n" ); document.write( "the ground is 0. \n" ); document.write( "so -16t^2+48t+64=0=t^2-3t-4, moving everything over and dividing by 16 \n" ); document.write( "(t-4)(t+1)=0 \n" ); document.write( "t=4 seconds. \n" ); document.write( "- \n" ); document.write( "want to know when s=64 \n" ); document.write( "so -16t^2+48t+64=64 \n" ); document.write( "or 16t^2=48t \n" ); document.write( "t=3 seconds \n" ); document.write( " |