document.write( "Question 1188419: The median existing home price of a home is 1988 was $90,600.00, and in 1994 it was $107,600.00. You wish to fit a linear equation to the points representing this data using 1980 as the base year. \r
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document.write( "a.Write and solve a system of equations that fit this model.\r
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document.write( "b.Interpret the slope in the context of the data.\r
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document.write( "c.By your model, what was the median price in 1991? \n" );
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Algebra.Com's Answer #819619 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! price P=(year-1980)x+ some constant \n" ); document.write( "ordered pair (8, 90600) and (14, 107,600) \n" ); document.write( "slope is difference in y 17000/ difference in x 6, \n" ); document.write( "that is $2833.3 \n" ); document.write( "point slope formula is y-y1=m(x-x1), m slope and (x1, y1) a point \n" ); document.write( "y-90600=2833.3(x-8) \n" ); document.write( "y=2833.3x+67934 \n" ); document.write( "slope is increase in the price per year. \n" ); document.write( "1991 is x=11 \n" ); document.write( "so price was in 1991: 2833.33*11+67934=$99,100.67 \n" ); document.write( " |