document.write( "Question 1188489: Peter is forty years old and his son is ten years old. How long will it take so that will Peter be twice as old as his son? \n" ); document.write( "
Algebra.Com's Answer #819577 by ikleyn(52803)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let x be the number of years to pass.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then your basic equation is this\r\n" ); document.write( "\r\n" ); document.write( " 40 + x = 2*(10+x)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and find x\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 40 + x = 20 + 2x\r\n" ); document.write( "\r\n" ); document.write( " 40 - 20 = 2x - x\r\n" ); document.write( "\r\n" ); document.write( " 20 = x\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. In 20 years.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "CHECK. In 20 years their ages will be 10+20 = 30 (the son) and 40 + 20 = 60 (the father).\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |