document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188295>Question 1188295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Labor Force Couples The percentage of couples where both parties are in the labor force is 52.1. Choose 5 couples at random. Find the probability that<BR>\n" );
document.write( "a. None of the couples have both persons working<BR>\n" );
document.write( "b. More than 3 of the couples have both persons in the labor force<BR>\n" );
document.write( "c. Fewer than 2 of the couples have both parties working\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819545 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the first is p(0) is  (1-p)^5=0.479^5=0.0252<BR>\n" );
document.write( "more than 3 means 4 or 5<BR>\n" );
document.write( "for p(4)=5C4*0.521^4*0.479^1, binomial formula. This equals 0.1765<BR>\n" );
document.write( "for p(5)=0.521^5=0.0384<BR>\n" );
document.write( "The answer is the sum or 0.2149<BR>\n" );
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document.write( "p(1) is 5*0.521*0.479^4=0.1371<BR>\n" );
document.write( "added to p(0) gives the probability  of fewer than 2, and that is 0.1623.  </SPAN>\n" );
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