document.write( "Question 112280:
\n" ); document.write( "The length of a rectangle is 8 cm mor than 3 times its width. the perimeter of the rectangle is 64 cm.
\n" ); document.write( "B. What is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #81953 by checkley71(8403)\"\" \"About 
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L=3W+8
\n" ); document.write( "PERIMETER=2L+2W
\n" ); document.write( "64=2(3W+8)+2W
\n" ); document.write( "64=6W+16+2W
\n" ); document.write( "64=8W+16
\n" ); document.write( "8W=64-16
\n" ); document.write( "8W=48
\n" ); document.write( "W=48/8
\n" ); document.write( "W=6 CM FOR THE WIDTH.
\n" ); document.write( "L=3*6+8
\n" ); document.write( "L=18+8
\n" ); document.write( "L=26 CM FOR THE LENGTH
\n" ); document.write( "PROOF
\n" ); document.write( "64=2*6+2*26
\n" ); document.write( "64=12+52
\n" ); document.write( "64=64
\n" ); document.write( "AREA=W*L
\n" ); document.write( "AREA=6*26
\n" ); document.write( "AREA=156 CM^2 ANSWER FOR THE AREA.\r
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