document.write( "Question 1188438: The sum of n term of a series is n^2+2n for all value of n.find the first three terms of the series \n" ); document.write( "
Algebra.Com's Answer #819522 by mccravyedwin(408)\"\" \"About 
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document.write( "The sum of n term of a series is n^2+2n for all value of n.find the first three terms of the series\r\n" );
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document.write( "The \"sum of the first 1 term\" is the first term. So substituting n=1 in n2+2n, gives 12+2(1) = 1+2 = 3. \r\n" );
document.write( "So the first term is 3.\r\n" );
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document.write( "The sum of the first 2 terms is found by substituting n=2 in n2+2n, which gives 22+2(2) = 4+4 = 8.  Since \r\n" );
document.write( "the \"sum of the first 1 term\" is 3, the second term is 8-3=5.\r\n" );
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document.write( "The sum of the first 3 terms is found by substituting n=3 in n2+2n, which gives 32+2(3) = 9+6 = 15.  Since \r\n" );
document.write( "the sum of the first 2 terms is 8, the second term is 15-8=7.\r\n" );
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document.write( "In fact the sequence is the odd numbers beginning with 3,\r\n" );
document.write( "3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,...\r\n" );
document.write( "Edwin
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