document.write( "Question 1188446: Find the minimum value of the quadratic y = 2x^2 - 8x + 10 by completing the square. Graph the resulting parabola. Thank you.
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Algebra.Com's Answer #819520 by Boreal(15235)\"\" \"About 
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rewrite as y=2(x^2-4x+5)
\n" ); document.write( "=2(x^2-2x+4)+2; be careful here as the \"4\" is preceded by a multiplier of 2, and the constant in the parentheses is therefore 8, and need 2 more outside the parentheses to recover the original equation.
\n" ); document.write( "=2(x-2)^2+2
\n" ); document.write( "The minimum point is therefore (2, 2), reverse the sign of h, leave the sign of k alone.
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2x%5E2-8x%2B10%29\"\r
\n" ); document.write( "\n" ); document.write( "x-value is -b/2a=8/4=2
\n" ); document.write( "y-value is therefore 8-16+10=2
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