document.write( "Question 1188415: A committee of four is to be selected from a group of twenty people. How many different committees are possible, given the following conditions?
\n" ); document.write( "One person is the chair, one person is the secretary, and the other two are responsible for refreshment clean up.
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Algebra.Com's Answer #819496 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Let's focus on the first two slots for now. The order matters because the chairperson is different from the secretary. \r
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\n" ); document.write( "\n" ); document.write( "We have 20 choices for the chairperson, then 19 choices for the secretary. That yields 20*19 = 380 permutations. Each time we arrive at a new seat, we count down by 1. Let A = 380 since we'll use it later.\r
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\n" ); document.write( "\n" ); document.write( "Once we've filled those two slots, we have two additional seats where order does not matter. Both refreshment cleanup people have the same role/job. \r
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\n" ); document.write( "\n" ); document.write( "We have 18 choices for the third slot and 17 choices for the fourth slot. That gives 18*17 = 306 permutations. However, order doesn't matter so we divide by 2 to get 306/2 = 153. This represents the number of ways to pick the remaining two spots on the committee. Let B = 153.\r
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\n" ); document.write( "\n" ); document.write( "Overall, we have A*B = 306*153 = 58140 different ways to select the four person committee.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 58140
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