document.write( "Question 1186993: A part of P10,000 is invested at 4% and the remainder at 3. ½%. The annual
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document.write( "income from both is P380. Find the amount of each investment. \n" );
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Algebra.Com's Answer #819490 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x equals the investment at 4%. \n" ); document.write( "y equals the investment at 3.5%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have two equations that need to be solved simultaneously.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 10000 \n" ); document.write( ".04x + .035y = 380\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first eqution by .04 and leave the second equation as is to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".04x + .04y = 400 \n" ); document.write( ".04x + .035y = 380\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".005y = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for y to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 20/.005 = 4000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes x equal to 10000 - 4000 = 6000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".04*6000 + .035*4000 = 240 + 140 = 380.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the solution is correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that 6000 is invested at 4% and 4000 is invested at 3.5%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |