document.write( "Question 1188398: megan takes 30 seconds to run 100m while her brother takes 20 secs. if megan is given a 200 metre head start how long would it take her brother to catch up to her \n" ); document.write( "
Algebra.Com's Answer #819484 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor has shown one good formal algebraic method for solving the problem. \n" ); document.write( "While a formal algebraic solution was probably wanted, you can get some good mental exercise by solving the problem informally using logical reasoning and some relatively easy mental arithmetic. \n" ); document.write( "For a fixed distance, the ratio of the times required by Megan and her brother are in the ratio 3:2. That means the ratio of their speeds is 2:3. \n" ); document.write( "In this problem, they are running for the same amount of time, so Megan will run 2/3 as far as her brother. A bit of mental calculations show that if 2/3 as far as her brother is 200m less than her brother, then the distances the two of them run are 400m and 600m. \n" ); document.write( "Megan runs 100m in 30 seconds and so takes 120 seconds to run 400m. \n" ); document.write( "Her brother runs 100m in 20 seconds and so takes 120 seconds to run 600m. \n" ); document.write( "So 120 seconds is the amount of time it takes her brother to catch up to her when she is given a 200m head start. \n" ); document.write( " \n" ); document.write( " |