document.write( "Question 1188380: Alice had twice as much money as Peter. After Alice spent 1/6 of her money
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\n" ); document.write( "(a) How much money did Alice and Peter have altogether at first?\r
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\n" ); document.write( "original amount of money did he spend on the bag?
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Algebra.Com's Answer #819461 by ikleyn(52771) $\"\"$ $\"About$

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\n" ); document.write( " Alice had twice as much money as Peter. After Alice spent 1/6 of her money
\n" ); document.write( "and Peter spent
\n" ); document.write( "2/3 of his money, they had a total of $720 left.
\n" ); document.write( "(a) How much money did Alice and Peter have altogether at first?
\n" ); document.write( "(b) Peter spent 3/4 of his remaining money on a bag. What fraction of his
\n" ); document.write( "original amount of money did he spend on the bag?
\n" ); document.write( "(Give your answer in its simplest form.)
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\n" ); document.write( "\n" ); document.write( "I will solve part (a) only.\r
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document.write( "Let x be the amount Peter had at first, in dollars.\r\n" );
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document.write( "Then Alice had 2x dollars.\r\n" );
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document.write( "Write equation for the total remaining money after spending, as you read the problem\r\n" );
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document.write( "    {{(5/6)(2x)}}} +  = 720  dollars.\r\n" );
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document.write( "To solve, multiply both sides of the equation by 6 and simplify\r\n" );
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document.write( "    10x + 2x = 6*720\r\n" );
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document.write( "       12x   = 6*720\r\n" );
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document.write( "         x   =  = 6*60 = 360.\r\n" );
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document.write( "ANSWER.  Peter had $360 at first;  Alice had twice of it, i.e. $720 dollars.\r\n" );
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document.write( "         Altogether, they had 360 + 720 = 1080 dollars, at first.\r\n" );
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