document.write( "Question 112317: An express train and a local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #81945 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! DISTANCE=RATE*TIME \n" ); document.write( "FOR THE EXPRESS TRAIN 50=2X(T-1) \n" ); document.write( "FOR THE LOCAL TRAIN 50=X*T \n" ); document.write( "2XT-2X=XT \n" ); document.write( "2XT-XT-2X0 \n" ); document.write( "XT-2X=0 \n" ); document.write( "X(T-2)=0 \n" ); document.write( "T-2=0 \n" ); document.write( "T=2 HOURS FOR THE LOCAL TRAIN. \n" ); document.write( "50=2X \n" ); document.write( "X=25 MPH FOR THE LOCAL TRAIN. \n" ); document.write( "50=2*25(2-1) \n" ); document.write( "2-1=1 HOUR FOR THE EXPRESS TRAIN. \n" ); document.write( "50=2*25*1 \n" ); document.write( "50=50 \n" ); document.write( " |