document.write( "Question 1188359: When the population growth of a certain city was first studied, the population was 22,000. It was found that the population P grows with respect to time t in years by the formula P=22,000(10exponential of 0.163t)\r
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Algebra.Com's Answer #819448 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the growth formula is either:\r
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\n" ); document.write( "\n" ); document.write( "f = p * (1 + r) ^ n\r
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\n" ); document.write( "\n" ); document.write( "or:\r
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\n" ); document.write( "\n" ); document.write( "f = p * e ^ (r * t)\r
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\n" ); document.write( "\n" ); document.write( "i don't understand p = 22,000 * 10 ^ .163t.\r
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\n" ); document.write( "\n" ); document.write( "i suspect you want f = p * e ^ (r * t)\r
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\n" ); document.write( "\n" ); document.write( "under that aswsumption, .....\r
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\n" ); document.write( "\n" ); document.write( "for the population to double, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "44,000 = 22,000 * e ^ (.163 * t)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the formula by 22,000 to get:\r
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\n" ); document.write( "\n" ); document.write( "2 = e ^ (.163 * t)\r
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\n" ); document.write( "\n" ); document.write( "take the natural log of both sides of the formula to get:\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = ln(e ^ (.163 * t)) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = .163 * t * ln(e) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = .163 * t\r
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\n" ); document.write( "\n" ); document.write( "solve for t to get:\r
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\n" ); document.write( "\n" ); document.write( "t = ln(2) / .163 = 4.252436691\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing t in the original requation of f = 22,000 * e ^ (.163 * t) with 4.252436691 to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 22,000 * e ^ (.163 * 4.252436691).\r
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\n" ); document.write( "\n" ); document.write( "solve for f to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 44000.\r
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\n" ); document.write( "\n" ); document.write( "to triple the growth, you'll go through the same steps from:\r
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\n" ); document.write( "\n" ); document.write( "66,000 = 22,000 * e ^ (.163 * t)\r
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\n" ); document.write( "\n" ); document.write( "and wind up with:\r
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\n" ); document.write( "\n" ); document.write( "ln(3) = .163 * t\r
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\n" ); document.write( "\n" ); document.write( "solve for t to get:\r
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\n" ); document.write( "\n" ); document.write( "t = ln(3) / .163 = 6.739952691\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing t in the original equation of f = 22,000 * e ^ (.163 * t) with that to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 22,000 * e ^ (.163 * 6.739952691) \r
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\n" ); document.write( "\n" ); document.write( "solve for f to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 66000.\r
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\n" ); document.write( "\n" ); document.write( "the equation can be graphed, as shown below:\r
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\n" ); document.write( "\n" ); document.write( "the coordinate points are in (x,y) format.\r
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\n" ); document.write( "\n" ); document.write( "x in the graph equation is the same as t in the algebra equation.\r
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\n" ); document.write( "\n" ); document.write( "y in the graph equation is the same as f in the algebra equation.\r
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\n" ); document.write( "\n" ); document.write( "what this means is:\r
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\n" ); document.write( "\n" ); document.write( "f = 22000 * e ^ (.163 * t) and y = 22000 * e ^ (.163 * x) are equivalent equations and will give you the same results.\r
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\n" ); document.write( "\n" ); document.write( "f and y represent the future value of the population.
\n" ); document.write( "t and x represent the number of years.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo
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